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Ch 17 - Waiting Line Analysis for Service Improvement
  
  - Elements of Waiting Line Analysis      
	
    
 
    (p751)
    - Arrival Characteristics
    
      - Size of source population - infinite or finite
 
      - Pattern of arrivals - usual assumption, arrivals satisfy Poisson distribution.
            Prob( n arrivals per unit of time ) = e-l ln / n!
            where l = average arrival rate per unit of time.
            To justify a Poisson distribution, click
        here and download my Poisson.xls. 
      - Behavior of arrivals
            Patient, balk (refuse to enter), renege (enter but leave before
        service). 
    
     - Waiting Line Characteristics
    
      - Length of line - infinite or finite
 
      - Discipline - first-in, first-out (FIFO)
 
    
     - Service Characteristics
    
      - Service time - constant or random.
            For random, usual assumption, exponential distribution.
            Prob( service time > t ) = e-µt
             where µ = average service rate per unit of time. 
      - Structures - see Fig 17.2, p755
            Single-server waiting line
            Multiple-server waiting line. 
    
   
  
  - Basic Single-Server Model
    
 
    (p759)
    - Arrival Characteristics
    
      - Size of source population  infinite
 
      - Pattern of arrivals - Poisson distribution.
 
      - Behavior of arrivals  patient
 
    
     - Waiting Line Characteristics
    
      - Length of line  infinite
 
      - Discipline - first-in, first-out (FIFO)
 
    
     - Service Characteristics
    
      - Service time - random with exponential distribution.
 
      - Structure - single server
 
    
     - *Relationships (p760)
    
      - L - average number of units in system (waiting and in service)
            L = l /( µ - l ) 
      - W - average time in system (waiting and in service)
            W = 1 /( µ - l )
      
     
    
     - *Example 17.1 - 
	Auxiliary Student Bookstore, p761. What is the average time spent
      waiting and in service?
    
      
      l = average arrival rate
        of customers = 24/hr
      
      - µ = average service rate with one employee = 30/hr
      
 
      - W - average time in system (waiting and in service)
            W = 1 /( µ - l ) = 1 /(30-24) = 0.167 hr or 10
        minutes
      
     
    
     - *Service Improvement Analysis
	(p762) - Should the Student 
	Bookstore employ another 
	person to assist the present operator?
	             
	(This analysis is not explicitly in the text.)
    
      - The two employees work together as one service team, 
		with a service rate of 40/hr.
		        They are 
		each paid $100 for an 8 hour day. 
      - The bookstore values its customers 
		time at twice their average annual salary, which is $50,000/year.
       Thus, the value of individual customer time is 
		$50/hour for a 2,000 hour work year.
        Customer time cost = (number of 
		customers/day) * (value of customer time) * (average time in system)
                    
		= (8*l 
		) * ($50/hr) * W   =   9600 * W
		
			
				| 
				   Number of   
				   Employees  | 
				
				     µ   
				  | 
				
				   Average   Time in   System ( W ) 
				  | 
				
				   Customer  
				   Time   Cost  | 
				
				   Service 
				  Cost 
				 | 
				
				   Total 
				   Cost  | 
			
			
				|        1 | 
				  30 | 
				   0.1667 | 
				   $1600 | 
				  $100 | 
				  $1700 | 
			
			
				|       
            2 | 
				  40 | 
				   0.0625 | 
				   
				  $600 | 
				  $200 | 
				  
				  $800 | 
			
		
  
      - The Bookstore should employ 2 people because the total cost is lower.
 
    
   
  Do assigned HW 
	- Problem 17-13.
  
  - Basic Multiple-Server Model
	     
    
 
    (p770)
    - Arrival Characteristics - same as single-server
 
    - Waiting Line Characteristics - same as single-server
 
    - Service Characteristics
    
      - Service Time - same as single-server
 
      - Structure - multiple servers 
		(p755)
 
    
     - *Relationships - see page 770
 
    - *Example 17.5 - 
	Student Health Service Center waiting room, p772. 
	 Should Center employ 3 or 4 
	nurses?
    
      
      l  = average arrival rate
        of students = 10/hr
 
      - µ = average service rate per nurse = 4/hr
      
      
 - With 3 nurses, W - average time in system 
               W = 0.60 hr or 36 minutes, see page 773. 
      - With 4 nurses, W = 0.30 hr or 18 minutes 
		(p773).
		       Note how adding 
		one more nurse cuts W in half  (W is a very nonlinear function). 
      - Assumptions (not in text)
      
        
        - The nurses are 
		each paid $200 for an 8 hour day.
 - The Health Center values
		customer (student) time spent waiting and in service 
		at $25 per hour.
        
 - Customer time cost  =  (number of 
		customers/day) * (value of customer time) * (average time in system)
                    
		= (8*l 
		) * ($25/hr) * W    =   
		 80 * ( $25 ) * ( W )   
		=   2000 * W 
      
      
        
          | 
               Number of 
            Nurses 
           | 
          
               Average
			Time 
			  in System ( W ) 
           | 
          
               Customer  
            Time Cost 
           | 
          
               Service  
            Cost 
           | 
          
               Total  
            Cost 
           | 
        
        
          |     3 | 
              .60 | 
              
			1,200 | 
              
			600 | 
            
			1,800 | 
        
        
          |     4 | 
              .30 | 
              
			   600 | 
              
			800 | 
            1,400 | 
        
      
       
       - The Health Center should employ 4 
		nurses because the total cost is lower.
		                            
		(This page was last edited on
		August 16, 2006
        .)