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Ch 17 - Waiting Line Analysis for Service Improvement
- Elements of Waiting Line Analysis
(p751)
- Arrival Characteristics
- Size of source population - infinite or finite
- Pattern of arrivals - usual assumption, arrivals satisfy Poisson distribution.
Prob( n arrivals per unit of time ) = e-l ln / n!
where l = average arrival rate per unit of time.
To justify a Poisson distribution, click
here and download my Poisson.xls.
- Behavior of arrivals
Patient, balk (refuse to enter), renege (enter but leave before
service).
- Waiting Line Characteristics
- Length of line - infinite or finite
- Discipline - first-in, first-out (FIFO)
- Service Characteristics
- Service time - constant or random.
For random, usual assumption, exponential distribution.
Prob( service time > t ) = e-µt
where µ = average service rate per unit of time.
- Structures - see Fig 17.2, p755
Single-server waiting line
Multiple-server waiting line.
- Basic Single-Server Model
(p759)
- Arrival Characteristics
- Size of source population infinite
- Pattern of arrivals - Poisson distribution.
- Behavior of arrivals patient
- Waiting Line Characteristics
- Length of line infinite
- Discipline - first-in, first-out (FIFO)
- Service Characteristics
- Service time - random with exponential distribution.
- Structure - single server
- *Relationships (p760)
- L - average number of units in system (waiting and in service)
L = l /( µ - l )
- W - average time in system (waiting and in service)
W = 1 /( µ - l )
- *Example 17.1 -
Auxiliary Student Bookstore, p761. What is the average time spent
waiting and in service?
l = average arrival rate
of customers = 24/hr
- µ = average service rate with one employee = 30/hr
- W - average time in system (waiting and in service)
W = 1 /( µ - l ) = 1 /(30-24) = 0.167 hr or 10
minutes
- *Service Improvement Analysis
(p762) - Should the Student
Bookstore employ another
person to assist the present operator?
(This analysis is not explicitly in the text.)
- The two employees work together as one service team,
with a service rate of 40/hr.
They are
each paid $100 for an 8 hour day.
- The bookstore values its customers
time at twice their average annual salary, which is $50,000/year.
Thus, the value of individual customer time is
$50/hour for a 2,000 hour work year.
Customer time cost = (number of
customers/day) * (value of customer time) * (average time in system)
= (8*l
) * ($50/hr) * W = 9600 * W
Number of
Employees |
µ
|
Average Time in System ( W )
|
Customer
Time Cost |
Service
Cost
|
Total
Cost |
1 |
30 |
0.1667 |
$1600 |
$100 |
$1700 |
2 |
40 |
0.0625 |
$600 |
$200 |
$800 |
- The Bookstore should employ 2 people because the total cost is lower.
Do assigned HW
- Problem 17-13.
- Basic Multiple-Server Model
(p770)
- Arrival Characteristics - same as single-server
- Waiting Line Characteristics - same as single-server
- Service Characteristics
- Service Time - same as single-server
- Structure - multiple servers
(p755)
- *Relationships - see page 770
- *Example 17.5 -
Student Health Service Center waiting room, p772.
Should Center employ 3 or 4
nurses?
l = average arrival rate
of students = 10/hr
- µ = average service rate per nurse = 4/hr
- With 3 nurses, W - average time in system
W = 0.60 hr or 36 minutes, see page 773.
- With 4 nurses, W = 0.30 hr or 18 minutes
(p773).
Note how adding
one more nurse cuts W in half (W is a very nonlinear function).
- Assumptions (not in text)
- The nurses are
each paid $200 for an 8 hour day.
- The Health Center values
customer (student) time spent waiting and in service
at $25 per hour.
- Customer time cost = (number of
customers/day) * (value of customer time) * (average time in system)
= (8*l
) * ($25/hr) * W =
80 * ( $25 ) * ( W )
= 2000 * W
Number of
Nurses
|
Average
Time
in System ( W )
|
Customer
Time Cost
|
Service
Cost
|
Total
Cost
|
3 |
.60 |
1,200 |
600 |
1,800 |
4 |
.30 |
600 |
800 |
1,400 |
- The Health Center should employ 4
nurses because the total cost is lower.
(This page was last edited on
August 16, 2006
.)